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4p^2+5=73
We move all terms to the left:
4p^2+5-(73)=0
We add all the numbers together, and all the variables
4p^2-68=0
a = 4; b = 0; c = -68;
Δ = b2-4ac
Δ = 02-4·4·(-68)
Δ = 1088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1088}=\sqrt{64*17}=\sqrt{64}*\sqrt{17}=8\sqrt{17}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{17}}{2*4}=\frac{0-8\sqrt{17}}{8} =-\frac{8\sqrt{17}}{8} =-\sqrt{17} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{17}}{2*4}=\frac{0+8\sqrt{17}}{8} =\frac{8\sqrt{17}}{8} =\sqrt{17} $
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